 | Benjamin Greenleaf - 1857 - 336 Seiten
...the left-hand period, and place its root on • the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by ZOO for a divisor, by which divide the dividend, and... | |
 | Charles Guilford Burnham - 1857 - 328 Seiten
...the left-hand period, and place its root as a quotient in division. III. Subtract the cube from said period, and to the remainder bring down the next period, for a dividend. IV. Multiply the square of the quotient by 300, calling it the triple square, and the, quotient by... | |
 | Benjamin Greenleaf - 1857 - 452 Seiten
...period, and write its root as the first figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the square of the root figure by 3, and to the product annex two ciphers for a trial divisor,... | |
 | Charles Guilford Burnham - 1857 - 342 Seiten
...quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see hoie often the divisor is contained in the... | |
 | Joseph Ray - 1857 - 408 Seiten
...right, after the manner of a quotient in division. Subtract the square of the root from the left per'od, and to the remainder bring down the next period for a dividend. 3rd. Double the root already found, and place it on the left for a divisor. Find how many times the... | |
 | Dana Pond Colburn - 1858 - 288 Seiten
...period, and place its root as the first figure of the required root. 3d. Subtract the square thus found from the left-hand period, and to the remainder bring down the next period, calling the result a dividend. 4th. Double the part of the root already found for a trial divisor.... | |
 | Benjamin Greenleaf - 1858 - 332 Seiten
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend, and... | |
 | Charles Haynes Haswell - 1858 - 350 Seiten
...Find the greatest cube in the left-hand period, and set its root in the quotient ; subtract the cube number from the lefthand period, and to the remainder bring down the second period for a new dividend. To three times the square of the root just found add three times... | |
 | Benjamin Greenleaf - 1858 - 456 Seiten
...period, and trrite its root as the jirst figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the, square of the root figure by 3, and to the product annex tiro ciphers for a trial diviior,... | |
 | Horatio Nelson Robinson - 1859 - 362 Seiten
...and write its root for the first figure in the required root; subtract the cube from the left hand period, and to the remainder bring down the next period for a/ dividend. III. At the, left of the dividend write three times the square of the first fyurc of the root, and... | |
| |
... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
