 | William Kinne - 1831 - 248 Seiten
...for the first figure of the root; and set the square number under the period, subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found on the left hand of the dividend for a divisor. 4. Consider... | |
 | Martin Ruter - 1831 - 190 Seiten
...in the left hand period, place the root of it in the quotient, subtract the cube from the left hand period, and to the remainder bring down the next period for a resolvend. 3. Square the quotient and multiply the square by 3 for a defective divisor. 4. Seek how... | |
 | Zadock Thompson - 1832 - 186 Seiten
...cube in the left hand period, and place its root in the quotient. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the quotient by 300, calling it the triple square, and the quotient by 30, calling... | |
 | Samuel Read Hall - 1832 - 294 Seiten
...highest figure in the root required. Subtract the square of the root already found from the left hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend,... | |
 | Zadock Thompson - 1832 - 186 Seiten
...highest figure in the root required. Subtract the square of the root already found from the left hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor; seek how many times the divisor is contained in the dividend... | |
 | Catharine Esther Beecher - 1833 - 296 Seiten
...greatest cube in the left hand period, and subtract it from that period. Place the root in the quotient, and to the remainder bring down the next period, for a dividend. 3. Square the root already found (understanding a cipher at the right) and multiply it by 3 for a divisor.... | |
 | Daniel Adams - 1833 - 268 Seiten
...period, and write its root as a quotient in division. Subtract the square number.from the left hand period, and to the remainder bring down the next period for a dividend. . III. Double the root already found for a divisor ; seek how many times the divisor is contained in... | |
 | William Templeton (engineer.) - 1833 - 224 Seiten
...period ; then from the first period subtract the greatest cube it contains ; put the root as a quotient, and to the remainder bring down the next period for a dividend. Find a divisor by multiplying the square of the root by 300 ; see how often it is contained in the... | |
 | Frederick Emerson - 1834 - 300 Seiten
...hand period, and write its root in the quotient. Subtract the square of this root from the left hand period, and to the remainder bring- down the next period for a dividend. Thirdly — Double the root already found, for a divisor. Ascertain how many times the divisor is contained... | |
 | Benjamin Snowden - 1835 - 108 Seiten
...and put its root for the first figure of the root sought. 2. — Subtract this cube from the first period, and to the remainder bring down the next period for a dividend. 3. — Find a divisor by multiplying the square of the root by 300. 4. — Divide the dividend by this... | |
| |
... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
