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" Multiply the second and third terms together, and divide their product by the first term , the quotient will be the answer... "
The Modern House-carpenter's Companion and Builder's Guide: Being a Hand ... - Seite 164
von William Allen Sylvester - 1883 - 210 Seiten
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The Federal Calculator: Or, A Concise System of Practical Arithmetic

William Slocomb - 1828 - 160 Seiten
...first and third terms to the same denomination, and the second to the lowest name mentioned in it. e 3. Multiply the second and third terms together, and divide their product by the first; the quotient will be the answer to the question, in the same denomination in which you left the second...
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Daboll's Schoolmaster's Assistant

Nathan Daboll - 1828 - 268 Seiten
...second term to the lowest name mentioned in it. , 3. Multiply the second and third terms tupethpr, and divide their product by the first term. the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought...
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The Juvenile Arithmetick, and Scholar's Guide: Illustrated with Familiar ...

Martin Ruter - 1831 - 190 Seiten
...it. Reduce, likewise, the first and second terms to the lowest denomination that either of them has. Then multiply the second and third terms together,...divide their product by the first term. The quotient thus obtained will be the answer. It will not be necessary to distinguish between direct and inverse...
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A New and Easy Introduction to the Mathematics: Containing. A system of ...

Ira Wanzer - 1831 - 408 Seiten
...; reduce them both to the same denomination, viz. to the lowest denomination mentiorfed in either.t Then multiply the second and third terms together, and divide their product by the first term, and the quotient will be the fourth term, or answer, in. the same denomination as the third term; which...
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A New System of Arithmetick: In which the Rules are Familiarly Demonstrated ...

William Ruger - 1832 - 282 Seiten
...term stands in different denominations, reduce it to the lowest denomination mentioned in that term : Then multiply the second and third terms together, and divide their product by the first term, and the quotient will be the fourth term or answer in the same denomination, of the second term, in...
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Practical and Mental Arithmetic: On a New Plan, in which Mental Arithmetic ...

Roswell Chamberlain Smith - 1833 - 228 Seiten
...lowest denomination mentioned, by Reduction. „,,,.., «u VI. How do you proceed in the. operation f A. Multiply the, second and third terms together, and...their product by the first term ; the quotient will bo the fourth term, or answer, in the same denomination with the third term. VII. How may this process...
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The North American Arithmetic: Part Third, for Advanced Scholars, Band 3

Frederick Emerson - 1834 - 300 Seiten
...the third term must be less than the fourth, make the less of the two remaining terms the first term, and the greater the second: then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. 1. Ifl buy 871 yards...
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Cobb's Explanatory Arithmetick, Number Two: Containing the Compound Rules ...

Lyman Cobb - 1835 - 246 Seiten
...denominations, you must also reduce it to the lowest denomination mentioned in that term. You must then multiply the second and third terms together, and divide their product by the first term, and the quotient will be the answer, or fourth term, in the same denomination of the second term, in...
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A System of Geometry and Trigonometry: With a Treatise on Surveying; in ...

Abel Flint - 1835 - 368 Seiten
...is calculated accordingly. GENERAL RULE. 1. State the question in every case, as already taught : 2. Multiply the second and third terms together, and divide their product by the first. The manner of taking natural sines and tangents from the tables, is the same as for logarithmic sines...
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Cobb's Explantory Arithmetick, Number Two: Containing the Compound Rules ...

Lyman Cobb - 1836 - 228 Seiten
...denominations, you must also reduce it to the lowest denomination mentioned in that term. You must then multiply the second and third terms together, and divide their product by the first term, and the quotient will be the answer, or fourth term, in the same denomination of the second term, in...
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