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" ... 3. Multiply the second and third terms together, and divide their product by the first term , the quotient will be the answer to the question, in the same denomination you left the, second term in, which may be brought into anv other denomination... "
Daboll's Schoolmaster's Assistant, Improved and Enlarged: Eing a Plain ... - Seite 100
von Nathan Daboll - 1823 - 240 Seiten
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The Tutor's Assistant, Or Comic Figures of Arithmetic

Alfred Crowquill - 1843 - 128 Seiten
...term mentioned. Multiply the second and third numbers together, and divide the product by the first; the quotient will be the answer to the question in the same denomination you left the second number in. SINGLE RULE OF THREE. EXAMPLES. If 1 lb. of sugar cost 4|d., what cost 54 Ib. ? Ib. d. Ib....
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Arithmetic on the Productive System: Accompanied by a Key and Cubical Blocks

Roswell Chamberlain Smith - 1843 - 312 Seiten
...and second terms to the same denomination, and the third term to the lowest denomination in it, then multiply the second and third terms together, and divide their product by the first, the quotient will be the fourth term or answer, in the same denomination vj'ilh the third term. CONTRACTIONS...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged : Being a Plain ...

Nathan Daboll - 1844 - 228 Seiten
...it. 3. Multiply the second and third terms together, and divide their product by the first term ; and the quotient will be the answer to the question, in...you left the second term in, which may be brought inti) any other denomination required. The method of proof is by inverting the question. [NOTE. —...
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Introduction to The National Arithmetic: On the Inductive System; Combining ...

Benjamin Greenleaf - 1844 - 184 Seiten
...lowest denomination mentioned in either, and the third term to the lowest denomination mentioned in it. Multiply the second and third terms together, and divide their product by the first, and the quotient is the answer in the same denomination to which the third is reduced. If any thing...
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Introduction to The National Arithmetic, on the Inductive System: Combining ...

Benjamin Greenleaf - 1844 - 184 Seiten
...lowest denomination mentioned in either, and the third term to the lowest denomination mentioned in it. Multiply the second and third terms together, and divide their product by the first, and the quotient is the answer in the same denomination to tohich the third is reduced. If any thing...
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A system of practical arithmetic

William Lane (of Worthing.) - 1845
...contains. Then multiply the second and third terms together, and divide the product by the first term, and the quotient will be the answer to the question, in the same denomination that the third term was reduced to ; which must be brought again, if necessary, to the highest denomination...
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Watson's Tutor's assistant; or, Complete school arithmetic

William Watson (of Beverley.) - 1845 - 180 Seiten
...mentioned in it. 3. — Multiply the second and third terms together and divide the product by the first, the quotient will be the answer to the question in the same name the second term was brought into. The method of proof is by inverting the question. EXAMPLES....
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Arithmetic, its principles and practice

James W. Kavanagh - 1846
...after the third, and the marks (: :) for equality between the means. Having now arranged the terms, we multiply the second and third terms together, and divide their product by the first, the resulting quotient, 98, being the reiuired answer in shillings. The pupil is to recollect that,...
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The University Arithmetic: Embracing the Science of Numbers, and Their ...

Charles Davies - 1846 - 399 Seiten
...proportion to be found, .and make the third statement in the same manner as the second was made. III. Then multiply the second and third terms together, and divide their product by the product of the first terms, and the quotient will be the answer sought. EXAMPLES. Let us first resolve...
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Pantology

Roswell Park - 1847 - 580 Seiten
...placed last of those two, and the greater of them will be the first. The question being thus stated, multiply the second and third terms together, and divide their product by the first; and the quotient will be the fourth term, or answer sought. A Compound Proportion, including the solution...
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