| Abel Flint - 1835 - 368 Seiten
...is calculated accordingly. GENERAL RULE. 1. State the question in every case, as already taught : 2. Multiply the second and third terms together, and divide their product by the first. The manner of taking natural sines and tangents from the tables, is the same as for logarithmic sines... | |
| Francis Walkingame - 1835 - 270 Seiten
...mentioned in it, then multiply the second and third terms together, and divide the product by the first; the quotient will be the answer to the question in the same denomination the third term was reduced to, and must be reduced to the highest denomination it admits of. Note.... | |
| Lyman Cobb - 1836 - 228 Seiten
...denominations, you must also reduce it to the lowest denomination mentioned in that term. You must then multiply the second and third terms together, and divide their product by the first term, and the quotient will be the answer, or fourth term, in the same denomination of the second term, in... | |
| Luther Ainsworth - 1837 - 306 Seiten
...the SECOND term to the lowest denomination mentioned in that term ; and if the proportion be direct, multiply the second and third terms together, and divide their product by the first term, and the quotient will be the fourth term or answer, in the same denomination you left the second term... | |
| Roswell Chamberlain Smith - 1837 - 306 Seiten
...than one denomination 1 Q. How do you proceed in the operation ? A. Multiply the second and tth'rd terms together, and divide their product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term. Q. How may this process of multiplying... | |
| Roswell Chamberlain Smith - 1838 - 304 Seiten
...it to the lowest denomination men tioned, by Reduction. Q. How do you proceed in the operation ? A. Multiply the second and third terms together, and...their product by the first term ; the quotient will be thé fourth term, or answer, in the same denomination with the third term. Q. How may this process... | |
| Roswell Chamberlain Smith - 1839 - 308 Seiten
...the third term consists of more than çjie denomination ? Q. How do you proceed in the operation ? A. Multiply the second and third terms together, and...product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term. Q. How may this process of multiplying... | |
| Jason M. Mahan - 1839 - 312 Seiten
...denomination mentioned. Multiply the second and third terms together, and divide the product by the first : the quotient will be the answer to the question, in the same denomination you left the third term in. Proof. — Invert the question ; that is, place the answer for the first term, the third... | |
| Benjamin Greenleaf - 1839 - 356 Seiten
...lowest denomination, mentioned in cither, and the third term to the lowest denomination mentioned in it. Multiply the second and third terms together, and divide their product by the first, and the quotient is the answer in the same denomination to which the third is reduced. Jf any thing... | |
| Robert Goodacre - 1839 - 320 Seiten
...the third term is greater than the first, and the answer must be greater than the second, therefore multiply the second and third terms together, and divide their product by the first, the quotient will be the answer in farthings, because the second term was left in farthings, vvhic... | |
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