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" ... 3. Multiply the second and third terms together, and divide their product by the first term , the quotient will be the answer to the question, in the same denomination you left the, second term in, which may be brought into anv other denomination... "
Daboll's Schoolmaster's Assistant, Improved and Enlarged: Eing a Plain ... - Seite 100
von Nathan Daboll - 1823 - 240 Seiten
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A System of Geometry and Trigonometry: With a Treatise on Surveying; in ...

Abel Flint - 1835 - 334 Seiten
...is calculated accordingly. GENERAL RULE. 1. State the question in every case, as already taught : 2. Multiply the second and third terms together, and divide their product by the first. The manner of taking natural sines and tangents from the tables, is the same as for logarithmic sines...
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Taplin's improved edition of Walkingame's Tutor's assistant. To which is ...

Francis Walkingame - 1835
...mentioned in it, then multiply the second and third terms together, and divide the product by the first; the quotient will be the answer to the question in the same denomination the third term was reduced to, and must be reduced to the highest denomination it admits of. Note....
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Cobb's Explantory Arithmetick, Number Two: Containing the Compound Rules ...

Lyman Cobb - 1836 - 216 Seiten
...denominations, you must also reduce it to the lowest denomination mentioned in that term. You must then multiply the second and third terms together, and divide their product by the first term, and the quotient will be the answer, or fourth term, in the same denomination of the second term, in...
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Practical Mercantile Arithmetic: In which the Theory and Practice of ...

Luther Ainsworth - 1837 - 272 Seiten
...the SECOND term to the lowest denomination mentioned in that term ; and if the proportion be direct, multiply the second and third terms together, and divide their product by the first term, and the quotient will be the fourth term or answer, in the same denomination you left the second term...
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Practical and Mental Arithmetic, on a New Plan, in which Mental Arithmetic ...

Roswell Chamberlain Smith - 1837
...than one denomination 1 Q. How do you proceed in the operation ? A. Multiply the second and tth'rd terms together, and divide their product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term. Q. How may this process of multiplying...
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Practical and Mental Arithmetic: On a New Plan, in which Mental Arithmetic ...

Roswell Chamberlain Smith - 1838 - 284 Seiten
...it to the lowest denomination men tioned, by Reduction. Q. How do you proceed in the operation ? A. Multiply the second and third terms together, and...their product by the first term ; the quotient will be thé fourth term, or answer, in the same denomination with the third term. Q. How may this process...
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Practical and Mental Arithmetic ...

Roswell Chamberlain Smith - 1839
...the third term consists of more than çjie denomination ? Q. How do you proceed in the operation ? A. Multiply the second and third terms together, and...product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term. Q. How may this process of multiplying...
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The Private Instructor, Or Mathematics Simplified: Comprising Every Thing ...

Jason M. Mahan - 1839 - 304 Seiten
...denomination mentioned. Multiply the second and third terms together, and divide the product by the first : the quotient will be the answer to the question, in the same denomination you left the third term in. Proof. — Invert the question ; that is, place the answer for the first term, the third...
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The National Arithmetic, on the Inductive System: Combining the Analytic and ...

Benjamin Greenleaf - 1839 - 305 Seiten
...lowest denomination, mentioned in cither, and the third term to the lowest denomination mentioned in it. Multiply the second and third terms together, and divide their product by the first, and the quotient is the answer in the same denomination to which the third is reduced. Jf any thing...
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Arithmetic. [With] Key, Band 1

Robert Goodacre - 1839
...the third term is greater than the first, and the answer must be greater than the second, therefore multiply the second and third terms together, and divide their product by the first, the quotient will be the answer in farthings, because the second term was left in farthings, vvhic...
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