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... 3. Multiply the second and third terms together, and divide their product by the first term , the quotient will be the answer to the question, in the same denomination you left the, second term in, which may be brought into anv other denomination...
Daboll's Schoolmaster's Assistant, Improved and Enlarged: Eing a Plain ... - Seite 100
von Nathan Daboll - 1823 - 240 Seiten
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Practical and Mental Arithmetic on a New Plan: In which Mental ..., Bücher 2

Roswell Chamberlain Smith - 1829 - 268 Seiten
...it to the lowest denomination mentioned, by Reduction. VI. How do you proceed in the operation ? A. Multiply the second and third terms together, and...product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term. VII. How may this process of...
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Practical and Mental Arithmetic: On a New Plan, in which Mental Arithmetic ...

...it to the lowest denomination mentioned, by Reduction. VI. How do you proceed in the operation ? A. Multiply the second and third terms together, and...product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term. VII . How may this process of...
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Lessons on arithmetic: in principle, and in practice: for the instruction of ...

Thomas Smith (of Liverpool.) - 1830 - 100 Seiten
...all the terms together that are not marked, and to divide the product by those that are marked ," and the quotient will be the answer to the question, in the same denomination as that in which you left the second term." Precepts without examples, are of little avail, whether...
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The Juvenile Arithmetick, and Scholar's Guide: Illustrated with Familiar ...

Martin Ruter - 1831 - 179 Seiten
...Reduce, likewise, the first and second terms to the lowest denomination that either of them has. Then multiply the second and third terms together, and...divide their product by the first term. The quotient thus obtained will be the answer. It will not be necessary to distinguish between direct and inverse...
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Conkling's Arithmetic: The Young Arithmetician's Guide to a Knowledge of ...

Thomas Conkling (W.) - 1831 - 275 Seiten
...following Ptule for Working the Question. 1. Multiply the second and third terms together, and divide the product by the first term- The quotient will be the answer to the question in the same name or denomination the second term was left in. This you must remember; for, by it, you can determine...
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A New and Easy Introduction to the Mathematics: Containing. A system of ...

Ira Wanzer - 1831 - 396 Seiten
...reduce them both to the same denomination, viz. to the lowest denomination mentiorfed in either.t Then multiply the second and third terms together, and divide their product by the first term, and the quotient will be the fourth term, or answer, in. the same denomination as the third term; which...
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The Tutor's Assistant: Being a Compendium of Arithmetic and a Complete ...

Francis Walkingame - 1832 - 208 Seiten
...term mentioned. Multiply the second and third numbers together, and divide the product by the first, the quotient will be the answer to the question in the same denomination you left the second number in. EXAMPLES. 1. If 1 Ib. of sugar cost 4Jrf. what cost 54 Ib. *?4{ ;tw 4 18 — Ans. £1.0.3...
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A New System of Arithmetick: In which the Rules are Familiarly Demonstrated ...

William Ruger - 1832 - 263 Seiten
...stands in different denominations, reduce it to the lowest denomination mentioned in that term : Then multiply the second and third terms together, and divide their product by the first term, and the quotient will be the fourth term or answer in the same denomination, of the second term, in...
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Practical and Mental Arithmetic on a New Plan: In which Mental Arithmetic is ...

Roswell Chamberlain Smith - 1833 - 268 Seiten
...lowest denomination mentioned, by Reduction. „,,,.., «u VI. How do you proceed in the. operation f A. Multiply the, second and third terms together, and...their product by the first term ; the quotient will bo the fourth term, or answer, in the same denomination with the third term. VII. How may this process...
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Cobb's Explanatory Arithmetick, Number Two: Containing the Compound Rules ...

Lyman Cobb - 1835 - 216 Seiten
...denominations, you must also reduce it to the lowest denomination mentioned in that term. You must then multiply the second and third terms together, and divide their product by the first term, and the quotient will be the answer, or fourth term, in the same denomination of the second term, in...
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