| Beriah Stevens - 1822 - 423 Seiten
...extreme is the divisor. 3. Place the divisor on the left hand, and the other extreme on the right ; then **multiply the second and third terms together, and divide their product by the first,** ami the quotient gives the answer ; which is always of the same name with the middle term. When the... | |
| Nathan Daboll - 1824 - 240 Seiten
...first and third terms may be of the same kind ; and the second term of the same kiml with the answer, **or thing sought. 2. Bring the first and third terms...their product by the first term ; the quotient will** b« the answer to the question, in the same denomination you left the second term in, which may be... | |
| Etienne Bézout - 1824 - 219 Seiten
...consequently, for performing the Simple Rule of Three Direct, a« explained in article (179), is as follows ; **Multiply the second and third terms together and divide their product by the first** ; the quotient will be the answer, or fourth term sought. -I he following examples will explain the... | |
| John White - 1826 - 108 Seiten
...first and third terms into the same denomination, and the second into the lowest name mentioned. 2. **Multiply the second and third terms together, and divide their product by the first,** and their quotient will be the answer, in the same denomination as that in which the second was left.... | |
| John Dozell - 1827 - 40 Seiten
...term mentioned. Multiply the second and third numbers together, and divide the product by the first, **the quotient will be the answer to the question in the same denomination** as you left the second number in. If there happen to be a remainder after the Division, reduce it into... | |
| Nathan Daboll - 1828 - 240 Seiten
...of the same kind with the answer, or thing sought. 2. Bring the first and third terms to the saaic **denomination, and reduce the second term to the lowest...together, and divide their product by the first term;** and the quotient will be the answer to tho questitfti, in the same denomination you left the second... | |
| Martin Ruter - 1828 - 166 Seiten
...Reduce, likewise, the first and second terms to the lowest denomination that either of them has. Then **multiply the second and third terms together, and...divide their product by the first term. The quotient** thus obtained will be the answer. It will not be necessary to distinguish between direct and inverse... | |
| William Slocomb - 1828 - 137 Seiten
...first and third terms to the same denomination, and the second to the lowest name mentioned in it. e **3. Multiply the second and third terms together, and divide their product by the first;** the quotient will be the answer to the question, in the same denomination in which you left the second... | |
| Nathan Daboll - 1828 - 240 Seiten
...it. 3. Multiply the second and third terms-togethicr, and divide th«ir product by the first term l **the quotient, will be the answer to the question, in the same** denemination you left the second term in, which may be brought into any other denomination required..... | |
| Nathan Daboll - 1829 - 240 Seiten
...third terms to the same denomination. and reduce the second term to the lowest n--- mtnuom u 11. ... **3. Multiply the second and third terms together and...the answer to the question, in the same denomination** yoo left the second term in, which may be brought into any oth er denomination required. '.fhe method... | |
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