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" ... 3. Multiply the second and third terms together, and divide their product by the first term , the quotient will be the answer to the question, in the same denomination you left the, second term in, which may be brought into anv other denomination... "
Daboll's Schoolmaster's Assistant, Improved and Enlarged: Eing a Plain ... - Seite 100
von Nathan Daboll - 1823 - 240 Seiten
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A New and Concise System of Arithmetick: Containing Vulgar, Decimal, and ...

Beriah Stevens - 1822 - 423 Seiten
...extreme is the divisor. 3. Place the divisor on the left hand, and the other extreme on the right ; then multiply the second and third terms together, and divide their product by the first, ami the quotient gives the answer ; which is always of the same name with the middle term. When the...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - 1824 - 240 Seiten
...first and third terms may be of the same kind ; and the second term of the same kiml with the answer, or thing sought. 2. Bring the first and third terms...their product by the first term ; the quotient will b« the answer to the question, in the same denomination you left the second term in, which may be...
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Elements of Arithmetic

Etienne Bézout - 1824 - 219 Seiten
...consequently, for performing the Simple Rule of Three Direct, a« explained in article (179), is as follows ; Multiply the second and third terms together and divide their product by the first ; the quotient will be the answer, or fourth term sought. -I he following examples will explain the...
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The tutor's expeditious assistant; being a system of practical arithmetic ...

John White - 1826 - 108 Seiten
...first and third terms into the same denomination, and the second into the lowest name mentioned. 2. Multiply the second and third terms together, and divide their product by the first, and their quotient will be the answer, in the same denomination as that in which the second was left....
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The elements of arithmetic

John Dozell - 1827 - 40 Seiten
...term mentioned. Multiply the second and third numbers together, and divide the product by the first, the quotient will be the answer to the question in the same denomination as you left the second number in. If there happen to be a remainder after the Division, reduce it into...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - 1828 - 240 Seiten
...of the same kind with the answer, or thing sought. 2. Bring the first and third terms to the saaic denomination, and reduce the second term to the lowest...together, and divide their product by the first term; and the quotient will be the answer to tho questitfti, in the same denomination you left the second...
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The Juvenile Arithmetick, and Scholar's Guide: Wherein Theory and Practice ...

Martin Ruter - 1828 - 166 Seiten
...Reduce, likewise, the first and second terms to the lowest denomination that either of them has. Then multiply the second and third terms together, and...divide their product by the first term. The quotient thus obtained will be the answer. It will not be necessary to distinguish between direct and inverse...
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The Federal Calculator: Or, A Concise System of Practical Arithmetic

William Slocomb - 1828 - 137 Seiten
...first and third terms to the same denomination, and the second to the lowest name mentioned in it. e 3. Multiply the second and third terms together, and divide their product by the first; the quotient will be the answer to the question, in the same denomination in which you left the second...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1828 - 240 Seiten
...it. 3. Multiply the second and third terms-togethicr, and divide th«ir product by the first term l the quotient, will be the answer to the question, in the same denemination you left the second term in, which may be brought into any other denomination required.....
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Daboll's Schoolmaster's Assistant: Improved and Enlarged: Being a Plain ...

Nathan Daboll - 1829 - 240 Seiten
...third terms to the same denomination. and reduce the second term to the lowest n--- mtnuom u 11. ... 3. Multiply the second and third terms together and...the answer to the question, in the same denomination yoo left the second term in, which may be brought into any oth er denomination required. '.fhe method...
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