 | Daniel Adams - 1830 - 294 Seiten
...and write its root as a quotient in division. Subtract the square number from the left haud period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor; seek how many times the divisor is contained in the... | |
 | Daniel Adams - 1830 - 280 Seiten
...and write its root as a quotient in division. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in... | |
 | Daniel Adams - 1831 - 276 Seiten
...and write its root as a quotient in division. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in... | |
 | Zadock Thompson - 1832 - 186 Seiten
...left hand period, and place its root in the quotient. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the quotient by 300, calling it the triple square, and the quotient by 30, call--... | |
 | Zadock Thompson - 1832 - 186 Seiten
...left hand period, and place its root in the quotient. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the quotient by 300, calling it the triple square, and the quotient by 30, calling... | |
 | Samuel Read Hall - 1832 - 294 Seiten
...figure in the root required. Subtract the square of the root already found from the left hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend,... | |
 | Catharine Esther Beecher - 1833 - 296 Seiten
...greatest cube in the left hand period, and subtract it from that period. Place the root in the quotient, and to the remainder bring down the next period, for a dividend. 3. Square the root already found (understanding a cipher at the right) and multiply it by 3 for a divisor.... | |
 | William Templeton (engineer.) - 1833 - 224 Seiten
...period ; then from the first period subtract the greatest cube it contains ; put the root as a quotient, and to the remainder bring down the next period for a dividend. Find a divisor by multiplying the square of the root by 300 ; see how often it is contained in the... | |
 | Daniel Adams - 1833 - 268 Seiten
...and write its root as a quotient in division. Subtract the square number.from the left hand period, and to the remainder bring down the next period for a dividend. . III. Double the root already found for a divisor ; seek how many times the divisor is contained in... | |
 | Frederick Emerson - 1834 - 300 Seiten
...period, and write its root in the quotient. Subtract the square of this root from the left hand period, and to the remainder bring- down the next period for a dividend. Thirdly — Double the root already found, for a divisor. Ascertain how many times the divisor is contained... | |
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... subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. " Place the double of the root, already found, on the lefl hand of the dividend for a divisor. 4. " Seek how often the divisor is contained... 
