 | Zachariah Jess - 1827 - 226 Seiten
...time is any number of years, and the rate per cenv pounds or dollars only ; . ' RULE THE COMMON WAY. Multiply the principal by the rate per cent, and divide the product by 100, the quotient will be the interest for one year, which multiply by the years given. RULE DECIMALLY.... | |
 | Michael Walsh - 1828 - 312 Seiten
...interest in Massachusetts is 6 per cent. Principal, is the money lent. Rate, is the sum. per cent, agreed on. Amount, is the principal and interest added together....the product by 100, and the quotient is the answer tor one year. When the principal is dollars only, multiply by the rate, and from the product point... | |
 | Michael Walsh - 1828 - 318 Seiten
...is the sum per cent. agreed on. Amount, is the principal and interest added together. GENERAL ROLE. Multiply the principal by the rate per cent. and divide...100, and the quotient is the answer for one year. When the principal is dollars only, multiply by the rate, and from the product point off two figures... | |
 | Montgomery Robert Bartlett - 1828 - 426 Seiten
...compound. SIMPLE INTEREST. Simple Interest is that which accrues on the principal on!) ^ for a given time. Rule. Multiply the Principal by the rate per cent, and divide the Product by 100, the Quotient will be the answer.— Thus:— CASE 1. tVhen the given time is one year. (1) What is... | |
 | Michael Walsh - 1828 - 318 Seiten
.../íníe, is the sum per cent, agreed on. Amount, is the principal and interest added together. GENERAI. RULE. Multiply the principal by the rate per cent, and divide the product by 10U, and the quotieniis the answer for one year. When the principal is dollars only, multiply by the... | |
 | Nathan Daboll - 1828 - 268 Seiten
...interest added together. CASE I. To find th« interest of any given sum for one year. RULE. Multiply th« principal by the rate per cent, and divide the product by 100 ; the quotient will be the answer. EXAMPLE8. 1. What is the interest of 59f. Us. 8id. for e»e year,... | |
 | James L. Connolly (mathematician.) - 1829 - 266 Seiten
...on. Amount is the principal and interest added together. To find the interest of any sum for a year. RULE. Multiply the principal by the rate per cent. and divide the product by 100, and the quotient will be the answer. Or say, As gl00 : 86 :rg 200 to glSforayear. • • EXAMPLES. 1. Lent a friend... | |
 | Nathan Daboll - 1829 - 268 Seiten
...principal and interest added together CASE I. To find the interest of any given sum for one year KULE. Multiply the principal by the rate per cent. and divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of 3iJl. Us. 8£d. for one year... | |
 | Michael Walsh - 1831 - 348 Seiten
...Massachusetts is 6 per cent. Principal, is the money lent. Rate, is the sum per cent. agreed on. Jlmouni, is the principal and interest added together. GENERAL...100, and the quotient is the answer for one year. TV hen the principal is dollars only, multiply by the rate, and from the product point off two figures... | |
 | 1831 - 198 Seiten
...1. To find the interest when the time is one year, and the rate per cent, is pounds or dollars only. RULE.* Multiply the principal by the rate per cent, and divide the product by 100: the quotient will be the interest for 1 year. PROOF. By the Single Rule of Three. EXAMPLES. 1. What... | |
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RULE. Multiply the principal by the rate per cent. and divide the product by 100, and the quotient is the answer for one year. 
