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" RULE.* Multiply the principal by the rate per cent, and divide the product by 100: the quotient will be the interest for 1 year. "
Arithmetic. [With] Key - Seite 196
von Robert Goodacre - 1839
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The American Arithmetic: Adapted to the Currency of the United States. To ...

Oliver Welch - 1826 - 242 Seiten
...1.60 21 226 32 292 10 1.05 11 106 22 2.32 33 298 11 1.055 SIMPLE I.VTEHEST IN LAWFUL MOSEY. RULE. — Multiply the principal by the rate per cent., and divide the product dy 100, the quotient is T year's interest; if months and days are mentioned in the time, find 1 year's...
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The American Tutor's Assistant, Improved: Or, A Compendious System of ...

Zachariah Jess - 1827 - 226 Seiten
...time is any number of years, and the rate per cenv pounds or dollars only ; . ' RULE THE COMMON WAY. Multiply the principal by the rate per cent, and divide the product by 100, the quotient will be the interest for one year, which multiply by the years given. RULE DECIMALLY. Multiply the...
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The Common School Manual: A Regular and Connected Course of Elementary ...

Montgomery Robert Bartlett - 1828 - 426 Seiten
...SIMPLE INTEREST. Simple Interest is that which accrues on the principal on!) ^ for a given time. Rule. Multiply the Principal by the rate per cent, and divide the Product by 100, the Quotient will be the answer.— Thus:— CASE 1. tVhen the given time is one year. (1) What is the Interest...
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Daboll's Schoolmaster's Assistant

Nathan Daboll - 1828 - 268 Seiten
...interest added together. CASE I. To find th« interest of any given sum for one year. RULE. Multiply th« principal by the rate per cent, and divide the product by 100 ; the quotient will be the answer. EXAMPLE8. 1. What is the interest of 59f. Us. 8id. for e»e year, at 61. par cent,...
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The Mercantile Arithmetic, Adapted to the Commerce of the United States, in ...

Michael Walsh - 1828 - 318 Seiten
...is the sum per cent, agreed on. Amount, is the principal and interest added together. GENERAI. RULE. Multiply the principal by the rate per cent, and divide the product by 10U, and the quotieniis the answer for one year. When the principal is dollars only, multiply by the...
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Connolly's Arithmetic: Or, The Ohio Accomptant: Being a Plain Practical ...

James L. Connolly (mathematician.) - 1829 - 266 Seiten
...Amount is the principal and interest added together. To find the interest of any sum for a year. RULE. Multiply the principal by the rate per cent. and divide the product by 100, and the quotient will be the answer. Or say, As gl00 : 86 :rg 200 to glSforayear. • • EXAMPLES....
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The Teacher's Assistant: Or, A System of Practical Arithmetic: Wherein the ...

1831 - 198 Seiten
...find the interest when the time is one year, and the rate per cent, is pounds or dollars only. RULE.* Multiply the principal by the rate per cent, and divide the product by 100: the quotient will be the interest for 1 year. PROOF. By the Single Rule of Three. EXAMPLES. 1. What is the interest...
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The Teachers' Assistant: Or, A System of Practical Arithmetic ...

1831 - 210 Seiten
...find the interest when the time is one year, and he rate per cent, is pounds or dollars only. RULE.* Multiply the principal by the rate per cent, and divide the product by 100: the quotient will be the interest for 1 year. PR00F. By the Single Rule of Three. EXAMPLES. 1. What is the interest...
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Mercantile Arith

Michael Walsh - 1831 - 348 Seiten
...is the sum per cent. agreed on. Jlmouni, is the principal and interest added together. GENERAL RULE. Multiply the principal by the rate per cent. and divide the product by 100, and the quotient is the answer for one year. TV hen the principal is dollars only, multiply by the...
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A New System of Arithmetick: In which the Rules are Familiarly Demonstrated ...

William Ruger - 1832 - 282 Seiten
...is not permitted to receive a greater per cent (han is allowed by the laws of his state. RULE. — Multiply the principal by the rate per cent, and divide the product by 100; but to divide by 100, you need only remove the separatrix two figures from its natural place towards...
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