 | Frederick Emerson - 1840 - 302 Seiten
...common difference. The sum of all the terms. PROBLEM. i. The extremes and number of terms being e;iven, to find the sum of all the terms. RULE. Multiply the sum of the extremes by the number of the terms, and half the product will be the sum of all the terms. See Theorem 4th. 1.... | |
 | Benjamin Greenleaf - 1841 - 334 Seiten
...difference of their ages ? Ans. 2 years. PROBLEM IL The first term, the last term, and the number of terms given to find the sum of all the terms. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum. 5. The extremes of an arithmetical series... | |
 | 1841 - 200 Seiten
...The first term, the last term, and the number of terms being given, to find the aggregate, or total sum of all the terms. RULE. — (') Multiply the sum of the extremes by the number of terms, and half the product will be the answer. Quertion 1. How do you find the aggregate... | |
 | Frederick Emerson - 1842 - 296 Seiten
...The number of terms. The common difference. The gum of all the terms. PROBLEM. I. The extremes and number of terms being given, to find the sum of all...the terms. RULE. Multiply the sum of the extremes by the number of the terms, and half the product will be the sum of all the terms. See Theorem 4th. 1.... | |
 | Osman Call - 1842 - 210 Seiten
...difference 1£, what is the number of terms? Ans. 4. THE FIRST AND LAST TERM, AND THE NUMBER OF TERMS GIVEN, TO FIND THE SUM OF ALL THE TERMS. RULE. — Multiply the sum of the first and last term by the number of terms, and half the product will be the sum of all the terms.... | |
 | Benjamin Greenleaf - 1843 - 340 Seiten
...difference of their ages ? Ans. 2 years. PROBLEM II. The first term, the last term, and the number of terms given to find the sum of all the terms. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum. 5. The extremes of an arithmetical series... | |
 | Nathan Daboll - 1843 - 254 Seiten
...increase ? Ans. Daily increase 2 miles. CASE III. The first term, last term, and number of terms given, tq find the sum of all the terms. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the answer. EXAMPLES. 1. A man bought 12 yards of... | |
 | Frederick Emerson - 1846 - 318 Seiten
...The number of terms. The common difference. The sum of all the terms. PROBLEM, i. The extremes and number of terms being given, to find the sum of all the terms. RULE. Multiply the $um of the extremes by the number of the terms, and half the product will 6e the sum of all the terms.... | |
 | Almon Ticknor - 1846 - 274 Seiten
...eldest 48 ; what was the common difference of their ages 1 Ans. 5 years. The first term, the last term, and the number of terms, being given, to find the sum of all the terms. RULE n. Multiply the sum of the extremes by the number of terms, and half the product will be the answer.... | |
 | William Vogdes - 1847 - 324 Seiten
...these being given, the other two may be readily found. § 164. CASE 1. The first term, the last tenu, and the number of terms, being given, to find the...the terms. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the answer. EXAMPLES. 1. The first term of an arithmetical... | |
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PROBLEM I. The first term, the last term, and the number of terms being given, to find the sum of all the terms. 
