 | Thomas William Silloway - 1858 - 236 Seiten
...likewise on the right hand of the divisor. Multiply the divisor by the last quotient-figure, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, 4th, Double the quotient already found for a partial divisor, and from these... | |
 | Benjamin Greenleaf - 1858 - 472 Seiten
...figure, for a true divisor. Multiply the true divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Multiply the square of (lie root figures already found by 3, and to the... | |
 | Benjamin Greenleaf - 1858 - 458 Seiten
...figure, for a true divisor. Multiply the true divisor by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Multiply the square of the root figures already found by 3, and to the product... | |
 | Elias Loomis - 1858 - 394 Seiten
...second figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a... | |
 | Horatio Nelson Robinson - 1859 - 362 Seiten
...divisor, 23, by the quotient figure, 2, and subtract the product, 46, from the part of the dividend used, and to the remainder bring down the next figure of the dividend, which is 0, making 20, for the second partial dividend. Then, since 23 is contained in 20 no times,... | |
 | Horatio Nelson Robinson - 1859 - 348 Seiten
...complete divisor ; multiply the complete divisor by the trial figure in the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Multiply the last figure of the last complete divisor ly 2, and annex... | |
 | Horatio Nelson Robinson - 1860 - 444 Seiten
...will be the complete divisor. V. Multiply the complete divisor by the trial figure ; subtract the. product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column... | |
 | James Bates Thomson - 1860 - 440 Seiten
...divisor ; multiply- the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, <£c.,... | |
 | Charles Davies - 1861 - 322 Seiten
...the divisor. IV. Multiply the divisor, thus augmented, by the lastfyurt of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if any of the products should be greater than the dividend, diminish... | |
 | Charles Davies - 1861 - 496 Seiten
...the divisor : IV. Multiply the divixor thus increased, by the last figure of the root j subtract the product from the dividend, and to the remainder bring down the next period for a new dividend: V. Double the whole root thus found, for a new trial divisor, -and continue... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
