 | Benjamin Naylor - 1850 - 334 Seiten
...exceed the left-hand period, which place in the quotient, and subtract the cube from the left-hand period, and to the remainder bring down the next period for a dividend. 3d. Take three times the square of the root for a defective divisor. 2A* 4th. Try how many... | |
 | Charles Guilford Burnham - 1850 - 350 Seiten
...the left-hand period, and place its root as a quotient in division. III. Subtract the cube from said period, and to the remainder bring down the next period, for a dividend. IV. Multiply the square of the quotient by 300, calling it the triple square, and the quotient... | |
 | 1852 - 202 Seiten
...period, and set its root on the right of the given number: subtract said square from the left hand period, and to the remainder bring down the next period for a dividual. 3. Double the root for a divisor, and try how often this divisor (with the figure used in the trial... | |
 | Joseph Ray - 1852 - 408 Seiten
...the right, after the manner of a quotient in division. Subtract the square of the root from the kft period, and to the remainder bring down the next period for a dividend. 3rd. Dovlle the root already found, and place it on the left for a divitor. Find how many... | |
 | Joseph Ray - 1848 - 250 Seiten
...the right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Double the root already found, and place it on the left for a divisor. Find how many... | |
 | Ezra S. Winslow - 1853 - 264 Seiten
...hand period, and place its root in the quotient ; subtract the square of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Multiply the root so far found — the figure in the quotient — by 2, for a divisor... | |
 | Horatio Nelson Robinson - 1854 - 306 Seiten
...period, and set its root on the right of the given number; subtract said square from the left-hand period, and to the remainder bring down the next period for a dividual. 3. Double the root for a divisor, and fry how often this divisor (with the figure used in the trial... | |
 | James Gray - 1854 - 120 Seiten
...root of that number as the first figure of the root sought : subtract the number itself from the said period, and to the remainder bring down the next period for a dividend. 3. Find a divisor by multiplying the square of the part of the root found by 300, divide... | |
 | Roswell Chamberlain Smith - 1856 - 334 Seiten
...last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total... | |
 | Charles Guilford Burnham - 1857 - 328 Seiten
...the left-hand period, and place its root as a quotient in division. III. Subtract the cube from said period, and to the remainder bring down the next period, for a dividend. IV. Multiply the square of the quotient by 300, calling it the triple square, and the, quotient... | |
| |
Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... 
