To multiply one decimal by another, multiply the figures as in whole numbers, and point off' as many decimal places in the .product as there are in the multiplier and the multiplicand together. Arithmetic - Seite 100von Charles Elsee - 1866 - 275 SeitenVollansicht - Über dieses Buch
| Henry Holmes Belfield - 1891 - 346 Seiten
...7983 by 800 ; by 600 ; by 500. 8. Multiply 82.5 by 3. When the multiplier is an integer, there are **as many decimal places in the product as there are in the** multiplicand. 9. Multiply $36.25 by 3 ; by 7 ; by 8. 96. 1. Multiply 738 by 146. PROCESS. ANALYSIS.... | |
| John Williston Cook, Nebraska C. Cropsey - 1893 - 304 Seiten
...there are in both factors. 18. Multiply .253 by .35. ,,-.-, Multiply as in whole numbers, and point **off as many decimal places in the product as there are in** both multiplicand and mul1265 tiplier. If there are not enough figures in 759 the product to fill the... | |
| Edward Brooks - 1893 - 213 Seiten
...either of these solutions we derive the following RULE. — Multiply as in whole numbers, and point **off as many decimal places in the product as there are in** both multiplier and multiplicand, prefixing ciphers when necessary. 2. Multiply 15.17 by .18. 3. Multiply... | |
| William Frothingham Bradbury - 1895 - 377 Seiten
...directly under tlie figure of the multiplier which produces it. 3. Add these partial products and point **off as many decimal places in the product as there are in the** multiplicand, and the result will be the true product. 62. PROOF. Multiply the multiplier by the multiplicand,... | |
| George Washington Hull - 1895 - 352 Seiten
...thousandths, or 5.904. 2D. 24.6 x .24 = *tf x ^ = !§8* = 5-904. RULE. Multiply as in whole numbers, and point **off as many decimal places in the product as there are in** both factors. Prefix ciphers to the product if it does not contain the required number of figures.... | |
| Edwin Crawford Hewett - 1896 - 253 Seiten
...multiplier had been hundredths; then how many in each? Do you see, then, that there will always be just **as many decimal places in the product as there are in the** multiplicand and multiplier counted together? Remember this. Now multiply twelve tenths by three hundredths.... | |
| John Williston Cook, Nebraska C. Cropsey - 1896 - 393 Seiten
...the product. RULE. In Multiplication of Decimal Fractions, .multiply as in simple numbers, and point **off as many decimal places in the product as there are in** multiplicand and multiplier. 189. PROBLEMS. Multiply : •1. .542 by 58. 3. .00436 by .8. 5. 6.028J... | |
| Samuel Wesley Baird - 1897
...5.2 by 4.6. OPERATION We multiply as in whole numbers, 5.2 and point off from the right as many 4.6 **decimal places in the product as there are in the multiplier and multiplicand together.** 23.92, Ans. a. b. с. 1. 4 X .36 .21 X 46 9 X 7.75 8. 7 X 47.3 2 .1 X 46 23 X 4.25 з. 3.4 X 76 4 .6... | |
| Heinrich Borchert Lübsen - 1897 - 333 Seiten
...multiplication exactly as with whole numbers, paying no attention to the decimal point ; then point **off as many decimal places in the product as there are in** both the factors together. If the product has fewer places than this requires, supply the deficiency... | |
| 1897
...decimals you may multiply the decimals together the same as in whole numbers, taking care to point **off as many decimal places in the product as there are in** both the multiplier and multiplicand ; and the reason for this is that if you change both to common... | |
| |