 | William Templeton (engineer.) - 1833 - 224 Seiten
...in the root ; add these three last found numbers together, and subtract this sum from the dividend ; to the remainder bring down the next period for a new dividend, and proceed as before. EXAMPLE. — Required the cube root of 44419494". 444194947(763 343 7 x 7 x... | |
 | Catharine Esther Beecher - 1833 - 296 Seiten
...and add these three results together for a subtrahend. 5. Subtract the subtrahend from the dividend. To the remainder bring down the next period, for a new dividend, and proceed as before. If it happens in any case, that the divisor is not contained in the dividend,... | |
 | Daniel Adams - 1833 - 268 Seiten
....divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend ; to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new divisor, and continue the operation as before, until all... | |
 | Frederick Emerson - 1834 - 300 Seiten
...Multiply the divisor thus completed, by the figure last placed in the root, and subtract the product from the dividend; and to the remainder bring down the next period for a new dividend. Thus proceed, till the whole root is extracted. Observe, that, when the divisor is not contained in... | |
 | Benjamin Snowden - 1835 - 108 Seiten
...greater than the dividend, put a less figure than the last to the root, and alter the work. 8. — To the remainder bring down the next period for a new dividend, with which proceed as with the first dividend, until all the periods are brought down. Prove the work by cubing the root... | |
 | Charles Davies - 1835 - 378 Seiten
...IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the whole root already found, for a new divisor, and continue the operation as before, until... | |
 | Lyman Cobb - 1835 - 246 Seiten
...subtrahend. 7. Substract the subtrahend from the dividend, and to tho remainder bringdown the^next period for a new dividend, with which proceed as before; And so on, till the whole is finishedNoi-K. — If the divisor can not be had in the dividend, put a cipher in... | |
 | James L. Connolly (mathematician.) - 1835 - 264 Seiten
...adding thereto SO times the product of the last figure of the root into the rest. Multiply, subtract, and to the remainder bring down the next period for a new resolvend : add together the last complete divisor, the number that completed it, and twice the square... | |
 | Benjamin Greenleaf - 1857 - 452 Seiten
...for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. To the last true divisor and the number immediately over it, add the square of the last root figure,... | |
 | Charles Guilford Burnham - 1857 - 342 Seiten
...cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from tlte dividend, and to the remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? Operation.... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
