 | John Mair - 1772 - 376 Seiten
...extremes, and common difference, to find the number of terms 5 that is, given I. II. IV. to End III. RULE. Divide the difference of the extremes by the common difference, and the quot plus unity is the number of terms, by Theorem IV. EXAMPLE I. A fetting out on a journey, travels... | |
 | 1801 - 446 Seiten
...fast term, the last term, and the common dIfference, to Jind the number of Serins. P.U1.E.* . jpivide the difference of the extremes by the common Difference, and the quotient, increased by i, is the number of terms required. . ~" EXAMPLES. * By the last problem,' the difference of the extremes,... | |
 | Nicolas Pike - 1802 - 350 Seiten
....iboo+i X 1000 " / =500500 Anfwer. 2 PROBLEM 3. Given the extremis and the common dtffsr~ fnce, to Jind the number of terms. RULE. — Divide the difference...extremes by the common difference, and the quotient increafed by i will be the number of terms required. EXAMPLES. I. The extremes are 3 and 39, and the... | |
 | Nicolas Pike - 1807 - 370 Seiten
...? 1000+ i X 1000 =500500 Anf<wer. 2 PROBLEM 3 Given the extremes and the common difference, tojlnd the number of terms. RULE — Divide the difference...extremes by the common difference, and the quotient increafed by i will be the number of terms required. EXAMPLES. i. The extremes are 3 and 39, and the... | |
 | Samuel Webber - 1808 - 466 Seiten
...distance 366 miles. PR0BLEM III. Given thefirst term, the last term, and the common difference^ tofmd the number of terms. RULE.* Divide the difference...quotient, increased by 1, is the number of terms required. * By the last problem, the difference of the extremes, divided by the number of terms less 1, gives... | |
 | Nicolas Pike - 1808 - 470 Seiten
...PROBLEM PROBLEM III. Given the extranet and the common difference, to fad the number of terms, RutE.* — Divide the difference of the extremes by the common difference, and the quotient increased by 1 will be the number of terms required. EXAMPLES. 1 st. The extremes are 3 and 39, and the common difference... | |
 | Nicolas Pike - 1809 - 312 Seiten
...ICOO+IXIOOO 5=500500 Ans. 2PROBLEM III. Giventhtextremtf -and the common difference> to find the numbir of terms. RULE. Divide the difference of the extremes by the common difference, and the quotient increafed by i wilt be the number of. terms required. EXAMPLES. i. The extremes are 3 and 39, and the... | |
 | 1811 - 230 Seiten
...ftrike in 12 hours ? extremes 1+- 12=13,x (i 12=) 6=78 A. 2; or 1н- 12=13 x 12=150(78 times. A. RULE 2. Divide the difference of the extremes by the common difference, and the quotient increafed by one is the number of terms. Ex. if a man gave his youngeft fon 400 S, the next 630, &c.... | |
 | Samuel Webber - 1812 - 260 Seiten
...of terms less 1 ; hence this quotient, augmented by 1, must be the answer to the question. fererice, and the quotient, increased by 1, is the number of...common difference 3 ; what is the number of terms ? 53 2 S^T 17 1 ~18 In any Arithmetical Progression, the sum of any two of its terms is equal to the... | |
 | Jeremiah Joyce - 1812 - 274 Seiten
...III. The extreme terms a and z, and common difference d being given, to find the number of terms n. RULE. Divide the difference of the extremes by the common difference, and the quotient increased by unity is the number sought : or + i ~ n. Ex. 1. When the extremes are 4 and 106, and the common difference... | |
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Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. 
