 Multiply the whole number by the numerator of the fraction, and divide the product by the denominator ; or divide the whole number by the denominator of the fraction, and multiply the quotient by the numerator.  Easy Introduction to Mathematics - Seite 307von Charles Butler - 1814Vollansicht - Über dieses Buch
 | Edmund Wingate - 1751 - 438 Seiten
...'|° = 30. 299. Hence if it be required to multiply an integer by a Fraction, multiply the integer by the Numerator of the Fraction and divide the product by the Denominator. For Example, the product of 48 by \ is = 6X5 = 30. That the methods above directed are true, may be... | |
 | Thomas Hodson - 1806 - 488 Seiten
...number in the upper line. Then multiply the laft number, thus found by the abfolute number (6)t in the numerator of the fraction, and divide the product by the denominator; then the remainder will be the true value of x required, provided the number of terms in the upper... | |
 | L. I. M. Chevigné - 1807 - 294 Seiten
...write . 5 We shall here observe, that to multiply a whole number by a fraction, we must multiply that number by the numerator of the fraction, and divide the product by the denominator of said fraction. Let us now return to the question proposed ; I say now, that it was not 3 I had to... | |
 | Osgood Carleton - 1810 - 264 Seiten
...то SIMPLE MULTIPLICATION. CASE I. When the multiplier is a fraction, as •§, -J, Sec. multiply by the numerator of the fraction, and divide the product by the denominator ; the quotient will be the true product : If the numerator be 1, divide by the denominator only, as... | |
 | Thomas Keith - 1810 - 478 Seiten
..."03859. PROPOSITION XI. t (P) To find the value of a quantity having a vulgar fraction for it; exponent. RULE. Multiply the logarithm of the given number by the numerator of the exponent, and divide the product by the denominator ; the quotient will be the logarithm of the quantity... | |
 | John Bonnycastle - 1813 - 456 Seiten
...be the root required. But if it be a compound root, or one that consists both of a root and a power, multiply the logarithm of the given number by the numerator of the index, and divide the product by the denominator, for the logarithm of the root sought. Observing,... | |
 | John Bonnycastle - 1818 - 326 Seiten
...be the root required. But if it be a compound root, or one that consists both of a root and a power, multiply the logarithm of the given number by the numerator of the index, and divide the product by the denominator, for the logarithm of the root sought. Observing,... | |
 | Beriah Stevens - 1822 - 436 Seiten
...|X5|3 = i||°=H3||s.=£5 13s. 1(M. or, without reducing, you may DTiultiply the given multiplicand by the numerator of the fraction, and divide the product by the denominator. EXERCISES. 1. Multiply 4 by TiT. Product 44. 2. Multiply 7| by | . Product 6|| . 3. Multiply 8| by... | |
 | John Bonnycastle - 1825 - 336 Seiten
...be the root required. But if it he a compound root, or one that consists both of a root and a power, multiply the logarithm of the given number by the numerator of the index, and divide the product by the denominator, for the logarithm of the root sought. Observing,... | |
 | Thomas Keith - 1826 - 504 Seiten
...'03859. PROPOSITION XI. (P) Toßndthe value of a quantity having a vidgai- fraction far its exponent. RULE. Multiply the logarithm of the given number by the numerator of the exponent, and divide the product by the denominator ; the qwotient will be the logarithm of the quantity... | |
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