...the Extremes and Ratio are ciren, to find Oí* Sum of the Series, we /tare tin: following easy RULE. Multiply the last term, by the ratio, from the product...subtract the first term, and divide the remainder by (he ratio, less 1 ; the quotient will be the sum of the eerie« required. « 9. If the extrem« be...

...terms given, which, being multiplied by the first term, will give the last term, or greater ex treats. 2 Multiply the last term by the ratio, from the product...the first term, and divide the remainder by ratio Jess (?ae for the sum of the series. EXAMPLE?. 1. A thresher wrought 20 da}-s, and received for the...

...multiplier, or decrease by a common divisor, are said to be in geometrical progression; as 3, 6, 12, 24, 48; and 48, 24, 12, 6, 3. The multiplier or divisor by...thresher wrought 20 days, and received for the first days labour 4 grains of wheat; for the second, 12; for the third, 36, &c. How much did his wages amount...

...of terms given, which multiply by the first term, that product is the last -term or greater extreme. Multiply the last term by the ratio, from the product...subtract the first term, and divide the remainder by the ratio lessjone; the quotient will be the sum of the series. EXAMPLES. I Sold 24 yards of Holland,...

...of terms given. 2. Multiply the product by the first term and that product will be the last term. 3. Multiply the last term by the ratio, from the product subtract the first term and divide the remain, tier by the ratio less one, for the sum of the series. Questions. What is Geometrical Progression...

...right hand must remain the game as in the geometrical term. Then to find the sum of all the terms, multiply the last term by the ratio ; from the product,...subtract the first term, and divide the remainder by the ratio, less one ; the quotient will be the sum of all the terms. Or shorter t thus : Involve the...

...than the number of terms given, which, being multiplied by the first term, will give the last terfln, or greater extreme. 2. Multiply the last term by the...20 days, and received for the first day's labour 4 grains of wheat; for the second, 12: for the third, 36, &c. How much did his wages amount to, allowing...

...when the extremes and ratio are given, to find the sum of the series, we have the following easy HULE. Multiply the last term by the ratio, from the product...subtract the first term, and divide the remainder by the ratio, less 1 ; the quotient will be the sum of the series required. ft If the extremes be 5 and...

...and sum 01' the series are found by this RULE. 1. Raise the ratio to the power whose index is one is than the number of terms given, which, being multiplied...1. A thresher wrought 20 days, and received for the Irst day's labour 4 grains of wheat; for the second, 12; ror the third, 36, &c. How much did his wages...

...lessll than the number of terms given, and multiply it by the first | term, will give the last term. 2. Multiply the last term by the ratio, from the product...subtract the first term, and divide the remainder by the ratio less 1, for the sum of the series. EXAMPLES. 1. A labourer wrought 20 days, and received...