 | George Lees - 1826 - 276 Seiten
...the next. Divide this number (omitting the last figure) by twice that part of the root already found, annex the result to the root and also to the divisor ; then subtract the product of the divisor thus augmented, by that figure of the root last obtained ; and... | |
 | Harvey Goodwin - 1846 - 500 Seiten
...found to form the subtrahend ; in the example 86 is multiplied by 6, which gives the subtrahend 516. If there be more periods to be brought down, the operation must be repeated. 2116 (46 16 55. On pointing in the extraction of the cube root. It may be shewn exactly in the same... | |
 | Barnard Smith - 1854 - 368 Seiten
...the first period, and to the remainder bring down the second period. Divide the number thus formed, omitting the last figure, by twice the part of the...now stands, by the part of the root last obtained, and subtract the product from the number formed, as above mentioned, by the first remainder and second... | |
 | Barnard Smith - 1857 - 740 Seiten
...the first period, and to the remainder bring down the second period. Divide the number thus formed, omitting the last figure, by twice the part of the...now stands, by the part of the root last obtained, and subtract the product from the number formed, as above mentioned, by the first remainder and second... | |
 | Isaac Todhunter - 1858 - 530 Seiten
...period. Divide this quantity, omitting the last figure, by twice the part of the root already found, and annex the result to the root and also to the divisor,...to be brought down the operation must be repeated. 242. Extract the square root of 611524 ; also of 10246401. 611524^782 10246401^3201 49 9 148J1 215... | |
 | Isaac Todhunter - 1860 - 620 Seiten
...period. Divide this quantity, omitting the last figure, by twice the part of the root already found, and annex the result to the root and also to the divisor, thfn multiply the divisor as it now stands by the part of the root last obtained for the subtrahend.... | |
 | Isaac Todhunter - 1863 - 302 Seiten
...period. Divide this quantity, omitting the last figure, by twice the part of the root already found, and annex the result to the root and also to the divisor;...to be brought down, the operation must be repeated. 302. Examples. Extract the square root of 132496, and of 5322249. 13249^364 $3222491,2307 66,1424 43J132... | |
 | Benjamin Greenleaf - 1863 - 338 Seiten
...ALGEBRA. Divide this quantity, omitting the last figure, by double the part of the root already found, and annex the result to the root, and also to the divisor. Multiply the divisor as it now stands by the part of the root last obtained, and subtract the product... | |
 | Benjamin Greenleaf - 1864 - 420 Seiten
...double the part of the root already found, and annex the result to the root, and also to the divisor. Multiply the divisor as it now stands by the part of the root last obtained, and subtract the product from the dividend. If there are more periods to be brought down, continue... | |
 | William Harris Johnston - 1865 - 478 Seiten
...part of the root already found ¡ annex the quotient to the root-figure and also to the divisor. Next, multiply the divisor as it now stands by the part of the root last obtained, and subtract the product from the number above mentioned, consisting of the first remainder and the... | |
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Divide the number thus formed, omitting the last figure, by twice the part of the root already obtained, and annex the result to the root and also to the divisor. Then multiply the divisor, as it now stands, by the part of the root last obtained, and... 
