 | William Crumpton - 1766 - 342 Seiten
...ree. ______ _.. tilintal 'Parallelogram. RTILE. Multiply the bafe by the perpendicular altitude (viz. the length by the breadth*) and the product will be the area or fuperficial content. ' • i|t!.. 1 i . '. i EXAMPLE. Let the fide of a fquare be 3 feet 10 inches;... | |
 | George Adams - 1813 - 648 Seiten
...work. OF TIMBER MEASURE. PROBLEM 1. Tofnd the area, or superficial content in feet in a board or plank. Multiply the length by the breadth, and the product will be the content required. Note. If the board is tapering, add the breadth of the two ends together, and take... | |
 | Nathan Daboll - 1815 - 250 Seiten
...— 160 square rods make an acre. Therefore, 26x26=676 sq. rods, and 676-4-160=4"i 36r. the Answer. ART. 2. To measure a parallelogram, or long square....product will be the area, or superficial content. EXAMPLE8. 1. A certain garden, in form of a long square, is 96ft. ;ong, and 54 wide; how many square... | |
 | Nathan Daboll - 1817 - 252 Seiten
...Therefore, 26X26-=676 sq. rods, and 676-*-160=4a. S6r. the ' ART. 2. To measure a parallelogram, or lofig square. RULE. Multiply the length by the breadth,...certain garden, in form of a long square, is 96 ft. long, and 54 wide; how many square feet of ground ar» contained in it ? 4ns. 96X^4=5 144 square feet.... | |
 | Nathan Daboll - 1818 - 246 Seiten
...— 160 square rods make an acre. Therefore, 26x26=676 sq. rods, and 676-4-160=-4o. 36r. the Jlnswer. ART. 2. To measure a Parallelogram, or long square....content. EXAMPLES. 1. A certain garden, in form of along square, is 96 ft, long, and 54 wide ; how many square feet of ground are contained in it ? Jlns.... | |
 | Nathan Daboll - 1818 - 246 Seiten
...— 160 square rods make an acre. Therefore, 26x26=676 sq. rods, and 676-7-160=4*. 36r. the Answer. ART. 2. To measure a Parallelogram, or long square. RULE. Multiply the length bv the breadth, and the product will be the area or superficial content. •» EXAMPLES. .. 1. A certain... | |
 | Nathan Daboll - 1820 - 256 Seiten
...160 square rods make an acre. Therefore, 26x26=676 Sq. rods, and 6r6-=-160==4i«. 36r. the Answer. ART. 2. To measure a parallelogram, or long square....certain garden, in form of a long square, is 96 ft. long, and 54 wide; how many square feet of ground are contained in it ? Aris. 96x54=5144 square feet.... | |
 | Matthew Iley - 1820 - 512 Seiten
...we have for the area 11924-6 on A, against 109-2 on B. PROBLEM II. To find the Area of a Rectangle. RULE. Multiply the length by the breadth, and the product will be the area. Let ABCD be a rectangle whereof the length is G3 inches, and the breadth 42 inches ; the area is required.... | |
 | Nicolas Pike - 1822 - 536 Seiten
...numbers, to the length , that distance, laid the same way from the breadth, will point out the answer. ART. 2. To measure a Parallelogram or long Square....product will be the area, or superficial content.* Let ABCD represent a parallelogram, whose A length is 5 feet, and breadth, 4 feet. Multiply 5 by 4.... | |
 | Beriah Stevens - 1822 - 436 Seiten
...four angles, the opposiles whereof are equal ; to find tbe superficial content thereof this is the rule : — Multiply 'the length by the breadth, and the product will be the superficial content or area. EXAMPLE. Let ABCD represent a parallelogram, whose length is 18, and breadth... | |
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To measure a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area, or superficial content. 
