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" RULE. Multiply the principal by the rate per cent. and divide the product by 100, and the quotient is the answer for one year. "
A New System of Mercantile Arithmetic: Adapted to the Commerce of the United ... - Seite 101
von Michael Walsh - 1807 - 274 Seiten
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Mathematics: Compiled from the Best Authors and Intended to be the ..., Band 1

1801
...or sum per cent, are calculated like Simple Interest. RULE.f j. Multiply the principal by the rate, and divide the product by 100 ; and the quotient is the answer for one year. 2. Multiply * Stock is a general name for public funds, and capitals of trading companies, the shares...
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A New and Plain System of Arithmetic: Containing the Several Rules of that ...

Elijah H. Hendrick - 1810 - 204 Seiten
...Simple and Compound.!, SIMPLE INTEREST is that which arifes from the principal only. General Rule. I. Multiply the principal by the rate per cent, and divide the product by loo, (or, which is the fame, cut-off two right hand figures in the pounds, which mint be reduced to...
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The American Tutor's Assistant Revised: Or, A Compendious System of ...

Zachariah Jess - 1810 - 210 Seiten
...only. CASE 1. When tfcfc time is any number of years, asd the rate per cent, pounds or dollars only ; RULE. Multiply the principal by the rate per cent, and divide the produél by 1 00, the quotient will be the interest for one year ; which multiply by the years given....
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The Teachers Assistant. Or, A System of Practical Arithmetic: Wherein the ...

1811 - 198 Seiten
...interest. CASE*1!. When the time is one year, and the rate per cent, is pounds or dollars only. * • RULE.» Multiply the principal by the rate per cent, and divide the product by 100. PROOF. , , By the Single Rule of Three. EXAMPLES. 1. What is the interest of 525 L. for 1 year, at...
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A System of Arithmetic

Samuel Webber - 1812 - 248 Seiten
...of which are transferable from one person to another. RULE.* 1. Multiply the principal by the rate, and divide the product by 100 ; and the quotient is the answer for one year. 2. Multiply the interest for one year by the given number of years, and the product is the answer for...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1815 - 240 Seiten
...principal and interest added together. CASE I. To find the interest of any given sum for one year. RULE. Multiply the principal by the rate per cent, and divide the product by 100 ; the quotient will be the answer. EXAMPLE!. 1. What is the interest of 39Z. lls. 8id. for one year...
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Daboll's Schoolmaster's Assistant, Improved and Enlarged: Eing a Plain ...

Nathan Daboll - 1823 - 240 Seiten
...principal and interest added together. CASE I. To find the interest of any given sum for one yeai» RULE. Multiply the principal by the rate per cent. and divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of S9/. Us. 8itI. for one year,...
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The Teachers' Assistant: Or a System of Practical Arithmetic

Stephen Pike - 1824 - 198 Seiten
...1. To find the interest when the time is one year, and the rate per cent. is pounds or dollars only. Multiply the principal by the rate per cent. and divide the product by 100: the quotient will be the interest for 1 year. PROOF. By the Single Rule of Three. EXAMPLES. 1. What...
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Daboll's Schoolmaster's Assistant, Improved and Enlarged

Nathan Daboll - 1825 - 240 Seiten
...principal and interest addeâ together. CASE i. Vb find {he interest of any given sum for one ysar. RULE. Multiply the principal by the rate per cent. and divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of 391. 11s. SJd. for one year....
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The American Arithmetic: Adapted to the Currency of the United States. To ...

Oliver Welch - 1826 - 227 Seiten
...045 10 1.60 21 226 32 292 10 1.05 11 106 22 2.32 33 298 11 1.055 SIMPLE I.VTEHEST IN LAWFUL MOSEY. RULE. — Multiply the principal by the rate per cent., and divide the product dy 100, the quotient is T year's interest; if months and days are mentioned in the time, find 1 year's...
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