 | Charles Hutton - 1770 - 518 Seiten
...trapezoide will be infinite, and it is then called, fometimes, a cylindroid. GENERAL RULE. To the fum of the areas of the two ends add four times the area of a fection parallel to and equally diftant from both ends, multiply the laft fum by the height and i of... | |
 | John McGregor (teacher of mathematics.) - 1792 - 532 Seiten
...being 72 feet. Anf. 89.5356 cubit-feet. , PROBLEM IX. Tcjlnd the folidity of the prifmoid. RULE I. To the areas of the two ends add four times the area of the middle feâion. Multiply the fum by the height, and $ the produft will be the folidity. RULE 2.... | |
 | Thomas Keith - 1817 - 306 Seiten
...*2618 (one-third of '7854), and then by the height, the last product will be the solidity. RULE II*. To the sum of the areas of the two ends, add four times the area of a section parallel to. * The first Rule, which is the same is that given for the priimoid, wai introduced into this work by... | |
 | Anthony Nesbit, W. Little - 1822 - 916 Seiten
...bushels. PROBLEM IX. 'To find the content of a vessel in the form of a prismoid, RULE, By the Pen. To the sum of the areas of the two ends, add four times...section parallel to, and equally distant from both ends ; multiply this sum by the perpendicular depth, and $ of the product will be the content in cubic inches.... | |
 | Anthony Nesbit - 1824 - 476 Seiten
...frustum of a square pyramid ; to find its. content in ale and wine gallons, ana matt bus/ids. RULE. To the sum of the areas of the two ends add four times the area of the middle section parallel t» them ; multiply this sum by the perpendicular depth, and J of the product... | |
 | Thomas Curtis - 1829 - 810 Seiten
...7140 solid inches, or 4-1319 solid feet. PROB. XXIX. To find the solidity of a promoid. Rule,— to the sum of the areas of the two ends add four times...equally distant from, both ends, and multiply the sum by one-tenth of the height for the solidity. Demonstration. — Let B zz the breadth of the greater end,... | |
 | John Bonnycastle - 1829 - 256 Seiten
...to be 17.14508 inches ? Ans. 3.1006 feet. PROBLEM XI. To find the solidity ofaprismoid. . RULE.* To the sum of the areas of the two ends add four times the area of a section parallel tq and equally distant from both ends, and this last sum multiplied by £ of the height will give the... | |
 | Thomas Curtis - 1829 - 878 Seiten
...in many cases it gives very erroneous results. The true method of finding the solidity is this : to the sum of the areas of the two ends, add four times the area of the middle section between them, and the sum multiplied by onelixth of the length will give the solidity.... | |
 | Jeremiah Day - 1831 - 418 Seiten
...what is the solidity ? Ans. 5040. PROBLEM VIII. Tofint} the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY i OF THE HEIGHT. Let L and... | |
 | Jeremiah Day - 1831 - 520 Seiten
...what is the solidity ? Ans. 5040. PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY £ OF THE HEIGHT. Let L and... | |
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RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity. 
