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" To find the area of a triangle, multiply the base by the perpendicular height, and take half the product. "
Manual of Rules, Tables & Data for Mechanical Engineers ... - Seite 15
von Daniel Kinnear Clark - 1878 - 984 Seiten
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A Course of Mathematics in Two Volumes for the Use of Academies as Well as ...

Charles Hutton - 1807 - 464 Seiten
...breadth 5 feet 3 inches. Ans. 21-^ square yards. PROBLEM II. To find tie Area of a Triangle. RULE 1. MULTIPLY the base by the perpendicular height, and take half the product for the area*. Or, multiply the one of these dimensions by half the other. measuring units in the breadth,...
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The principles of architecture, Band 1

Peter Nicholson - 1809 - 426 Seiten
...the' area of a rhomboides ABCD, whose length AB is l6f. 3i. and the height DE 5f. 6i. ? PROBLEM II. To find the area of a triangle. Multiply the base by the perpendicular height, and half the product will be the area. EXAMPLE 1. I What is the area of a triatgk ABC, the base AB being...
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A Course of Mathematics ...: Composed for the Use of the Royal Military ...

Charles Hutton - 1811 - 442 Seiten
...height 5 feet 3 inches. Ans. 21T7T square yards. PROBLEM II. • To find the Area of a Trianglt. RuLE 1. MULTIPLY the base by the perpendicular height, and take half the product for the area *. Or, multiply the one of these dimensions by half the other. measuring units in the...
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A Course of Mathematics: For the Use of Academies, as Well as Private ...

Charles Hutton - 1822 - 616 Seiten
...breadth 5 feet 3 inches. Ans. 21 -fa square yards. PROBLEM IT To find the Area of a Triangle. RULE I. MULTIPLY the base by the perpendicular height, and take half the product for the area.* Or, multiply the one of these dimensions by half the other. in the length, repeated...
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The Operative Mechanic, and British Machinist: Being a Practical Display of ...

John Nicholson (civil engineer.) - 1825 - 1008 Seiten
...the area of a rhombus, whose length is 6 chains, and perpendicular height 5. - 5 5 Ansr. 30 Proli. 2. To find the Area of a Triangle. /.'•'/..• ]. Multiply the base by the perpendicular height, and half the product will be the area. Rule 2. When the three sides only are given : Add the three sides...
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A Popular Course of Pure and Mixed Mathematics ...: With Tables of ...

Peter Nicholson - 1825 - 1046 Seiten
...16 3 1625 5 6 55 D С 9 81 8125 8125 f. 89.375 Л 89 4 6 f. i ii Ans. 89 ft. 4 in. 6 parts. Prob. 2. To find the area of a triangle. Multiply the base by the perpendicular height, and half the product will be the area. Ex. What is the area of a triangle ABC, the base AB being 12f. 3i....
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The Arithmetical Manual

Samuel Read Hall - 1832 - 294 Seiten
...breadth, or height, and the product will be the area • as above, 8 ft. X 3=24, the area of ABCD. To find the area of a Triangle, — Multiply the base...the perpendicular height, and take half the product for the area. The reason for the above rule will be evident from the illustration of the preceding...
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The parent's guide to a liberal ... education; containing a selection of ...

Robert Simson (master of Colebrooke house acad, Islington.) - 1838 - 206 Seiten
...the area. Let the sides of a rectangle be 12 and 9, what isits area? 12 X 9=108 the area. How do you find the area of a triangle ? Multiply the base by the perpendicular height, and half the product will be the area. Find the area of a triangle, of which the base is 115, and perpendicular...
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Call's Decimal Arithmetic: On a New and Improved Plan Throughout, Comprising ...

Osman Call - 1842 - 200 Seiten
...the length being 7, and the perpendicular being 4? Ans. 28. TO FIND THE AREA OF A TRIANGLE. RULE. — Multiply the base by the perpendicular height, and take half the product for the area. What is the area of a triangle, the base being 9, and the perpendicular 8 £ 1 Ans. 38J....
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An Encyclopædia of Architecture: Historical, Theoretical, and Practical

Joseph Gwilt - 1842 - 1114 Seiten
...-25 = 1 94 -25, and ^— = 21 -584 yards. 1215. PROBLEM II. To ßnd the area of a triangle. Rule 1. Multiply the base by the perpendicular height, and take half the product for the area. Or multiply either of these dimensions by half the other. The truth of this rule is evident,...
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