 | James Thompson - 1808 - 176 Seiten
...area of a trafiezoid, or quadrangle, <u'o cf •whose opposite sides are parallel. RULE — Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product •will be the area. EXAMPLES. 13. Required the area of a trapezoid whose parallel... | |
 | Matthew Iley - 1820 - 512 Seiten
...Content, for an Inch in Depth, of a Quadrilateral having two Parallel unequal Sides. RULE. By the Pen. Multiply half the sum of the parallel sides by the perpendicular distance between them, and divide the product by the number of cubic inches in the proposed integer. By the Sliding Rule.... | |
 | Anthony Nesbit - 1824 - 476 Seiten
...is its area ? Ans. 1131^.2 in. 9 pa. PROBLEM VIII. To find the area of a Irapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. Or, half the sum of the sides multiplied by their distance will... | |
 | Thomas Hornby (land surveyor.) - 1827 - 318 Seiten
...00000000 2.40000 40 16.00000 Ans. 0A. 2n. 16p. PROBLEM 3. To find the Area of a Trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. EXAMPLE. Required the area of the trapezoid AB CD, whose parallel... | |
 | John Bonnycastle - 1829 - 256 Seiten
...the area of a trapezoid, or a quadrangle, two of whose opposite sides are parallel. RULE.* Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides... | |
 | Edinburgh encyclopaedia - 1830 - 856 Seiten
...trapezoid is a quadrilateral, of which two opposite sides are parallel but not equal. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product is the area. In the trapezoid ABCD, draw the diagonal AC, and from its extremities... | |
 | William Galbraith - 1834 - 454 Seiten
...readily by logarithms. 3. Trapezium. — Multiply the base into half the sum of the perpendiculars. 4. Trapezoid. — Multiply half the sum of the parallel...sides by the perpendicular distance between them. fi. Irregular Polygon. — Divide it into triangles, find their areas, the sum of these will be the... | |
 | 1836 - 488 Seiten
...together half the sum and the three remainders, and extract the square root of the product. To ßnd the area of a trapezoid. Multiply half the sum of the parallel sides into their perpendicular distance. To ßnd ike area of a trapezium Divide the whole figure into triangles,... | |
 | B[enjamin] Franklin Callender - 1836 - 226 Seiten
...the area of a triangle, the sides of which are 75, 100, and 125 ? ANS. 3750. SECTION Xt. Trapezoid. To find the area of a Trapezoid. Multiply half the sum of the two parallel sides by the itude, the product is the area. 1. What is the area of a trapezoid the parallel... | |
 | Robert Simson (master of Colebrooke house acad, Islington.) - 1838 - 206 Seiten
...12, required the length of the hypotenuse. ^ 16s + 122 = 20, the length of the hypotenuse. HoW do you find the area of a trapezoid ? Multiply half the sum...sides by the perpendicular distance between them, and the product will be the area of the trapezoid. What is the area of a trapezoid, its parallel sides... | |
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To find the area of a trapezoid, multiply half the sum of the parallel sides by the perpendicular distance between them ; the product will be the area. 
