A Key Containing the Statements and Solutions of Questions in Prof. Charles Davies' New Elementary Algebra: For the Use of Teachers OnlyA.S. Barnes, 1859 - 72 Seiten |
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Seite 41
... Completing the square , x = ---- a2n2 n2 - - b2n2 ; b2n2 - m2 2bn2 b2n4 + 222 ( n2 - m2 ) 2 a2n2 - b2n2 b2n + + ( — m2 ) ? n2 - m2 Multiplying the numerator and denominator of the first ― m2 , so as to reduce term of the 221. ] 41 ...
... Completing the square , x = ---- a2n2 n2 - - b2n2 ; b2n2 - m2 2bn2 b2n4 + 222 ( n2 - m2 ) 2 a2n2 - b2n2 b2n + + ( — m2 ) ? n2 - m2 Multiplying the numerator and denominator of the first ― m2 , so as to reduce term of the 221. ] 41 ...
Seite 44
... completing the square , x2 - 675 ( 675 ) 2 675 ( 675 ) 2 -x + = + 48 ( 96 ) 2 48 ( 96 ) 2 = = 1350 ( 675 ) 2 + 96 ( 96 ) 2 1350 X 96 ( 96 ) 2 ( 675 ) 2 + 96 585225 ( 96 ) Then , by extracting the square root of both members , and taking ...
... completing the square , x2 - 675 ( 675 ) 2 675 ( 675 ) 2 -x + = + 48 ( 96 ) 2 48 ( 96 ) 2 = = 1350 ( 675 ) 2 + 96 ( 96 ) 2 1350 X 96 ( 96 ) 2 ( 675 ) 2 + 96 585225 ( 96 ) Then , by extracting the square root of both members , and taking ...
Seite 45
... Completing the square , hence , x2 10x + 25 = 21 + 25 = 4 ; x = 5 ± √√4 = 52 = 7 , and 3 . ( 10. ) Let x denote the distance traveled in one hour ; then , х 2 will denote the distance when he travels 2 miles an hour slower . 105 Then ...
... Completing the square , hence , x2 10x + 25 = 21 + 25 = 4 ; x = 5 ± √√4 = 52 = 7 , and 3 . ( 10. ) Let x denote the distance traveled in one hour ; then , х 2 will denote the distance when he travels 2 miles an hour slower . 105 Then ...
Seite 53
... Completing the square , 2268 ( 2268 ) 2 - -y + 20412 ( 2268 ) 2 = + 49 ( 98 ) 2 49 ( 98 ) 2 ; and y2 2268 ( 2268 ) 2 -y + 40824 X 98 ( 2268 ) 2 49 ( 98 ) 2 + ( 98 ) 2 5 ( 98 ) 2 which , after performing the operations indicated , gives ...
... Completing the square , 2268 ( 2268 ) 2 - -y + 20412 ( 2268 ) 2 = + 49 ( 98 ) 2 49 ( 98 ) 2 ; and y2 2268 ( 2268 ) 2 -y + 40824 X 98 ( 2268 ) 2 49 ( 98 ) 2 + ( 98 ) 2 5 ( 98 ) 2 which , after performing the operations indicated , gives ...
Seite 54
... completing the square , hence , x = 7.5 ; x2 .5.0625 = 7.5625 ; - x = .25 ± √7.5625 = 3 , by taking the positive root . ( 12. ) Let the greater number be denoted by x , and the less by y . Then , by first condition , ( x + y ) x = 77 ...
... completing the square , hence , x = 7.5 ; x2 .5.0625 = 7.5625 ; - x = .25 ± √7.5625 = 3 , by taking the positive root . ( 12. ) Let the greater number be denoted by x , and the less by y . Then , by first condition , ( x + y ) x = 77 ...
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A Key Containing the Statements and Solutions of Questions in Prof. Charles ... Charles Davies Keine Leseprobe verfügbar - 2016 |
A Key Containing the Statements and Solutions of Questions in Prof. Charles ... Charles Davies Keine Leseprobe verfügbar - 2016 |
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