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" Page 70, find the least common multiple of all the denominators of the given fractions, and it will be the common denominator required. "
Rose's New Arithmetic: An Explanatory and Practical Arithmetic, Adapted to ... - Seite 113
von John Rose - 1835 - 180 Seiten
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Mathematics: Compiled from the Best Authors and Intended to be the ..., Band 1

1801 - 446 Seiten
...fractions to others, which shall have tit least common denominator. 1. Find the least common multiple of all the- denominators of the given fractions, and it will be the common cle? nominator required. 2. Divide the common denominator by the denominator of each fraction, and...
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The New Complete System of Arithmetick: Composed for the Use of the Citizens ...

Nicolas Pike - 1807 - 370 Seiten
...which Jbalt haw the leaft common denominator. 1. By Prob. 2, page 70, find the leaft common multiple of all the denominators of the given fractions, and it will be the common denominator required. 2. Divide the common denominator by the denominator of each fraction, and multiply the quotient by...
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Mathematics: Compiled from the Best Authors, and Intended to be the ..., Band 1

Samuel Webber - 1808 - 466 Seiten
...consequently their values'are not altered. Thus in the first example ; 1 x5x7 x5x7 5 x2x7 x2x7 x2x5 x2x5 tors of the given fractions, and it will be the common denominator required. 2. Divide the common denominator by the denominator of each fraction, and multipy the quotient by the...
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A System of Arithmetic: Reprinted from the Mathematical Text-book

Samuel Webber - 1812 - 260 Seiten
...them ; it is therelore manifest that proper parts may be taken for aH the numerators required. tors of the given fractions, and it will be the common denominator required. 2. Divide the common denominator by the denominator of each fraction, and multiply the quotient by...
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Easy Introduction to Mathematics, Band 1

Charles Butler - 1814 - 540 Seiten
...common multiple of all the denominators by Art. 169, and it will be the common denominator required. II. Divide the common denominator by the denominator of...fraction, and multiply the quotient by the numerator, the several products will be the numerators, which place over the common denominator for the answer...
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Daboll's Schoolmaster's Assistant, Improved and Enlarged: Being a Plain ...

Nathan Daboll - 1817 - 252 Seiten
...reducing fractions to the least common denominator. (By Rule, page 155) find the least common multiple of all the denominators of the given fractions, and it will be the common denominator required, in which divide each particular denominator, and multiply the quotient by its •wn numerator for a...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - 1818 - 246 Seiten
...reducing fractions to the least common denominator. (By Rule, page 155) find the least common multiple of all the denominators of the given fractions, and it will be the common denominator required, in which divide each particular denominator, and multiply thfe quotient by its awn numerator for'a...
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A New and Concise System of Arithmetick: Containing Vulgar, Decimal, and ...

Beriah Stevens - 1822 - 436 Seiten
...common denominator. RULE. -v . 1. By problem 2, find the least cominnm multiple of ;dl the denominniorii of the given fractions, and it will be the common denominator required. 2. Divide'the common denominator by each particular denominator of ttie given fractions, and multiply...
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An Elementary Treatise on Algebra: Theoretical and Practical ...

James Ryan - 1826 - 430 Seiten
...II. 152. Find the least common multiple of all the denominators of the given fractions, (Art. 147), and it will be the common denominator required. Divide...common denominator by the denominator of each fraction, separately, and multiply the quotient by the respective numerators, and the products will be the numerators...
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Pike's System of Arithmetic Abridged: To which are Added Appropriate ...

Nicolas Pike, Dudley Leavitt - 1826 - 214 Seiten
...have the least common denominator. RULE. — Find the least common multiple (by problem II, page 72,) of all the denominators of the given fractions, and it will be the common denominator required ; then divide the common denominator by the denominator of each fraction, and multiply the quotient...
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