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" To find the interest of any given sum for one year, RULE. Multiply the principal by the rate per cent and divide the product by 100 ; the quotient will be the interest for one year. "
The accomptant's oracle; or, key to science, a treatise of common arithmetic - Seite 144
von Wardhaugh Thompson - 1771
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A Treatise on Arithmetic

J. Brookes - 1776 - 364 Seiten
...fum of money, for fome determined fpace of time. RULE I. When the Intereft is required for a Year, multiply the Principal by the rate per Cent, and divide that Product by loo, the Quotient is the Intercft required. What's the Intereft of 1 79/. for a Year, at 5/. per Cení,...
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The Tutor's Assistant Modernised: Or, A Regular System of Practical ...

Thomas Peacock - 1791 - 302 Seiten
...principal and intereft is called the amount, J, « ' CASE CASE I. To find the inf ereft of any fum of money for a year. RULE. Multiply the principal by the rate per cent, then, divide the product by loo, and 'the quotient will be the intereft required. Or, take the aliquot...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1815 - 250 Seiten
...is the principal and interest added together. CASE I. To find the interest of any given sum for one year. RULE. Multiply the principal by the rate per cent, and divide the product by 100 ; the quotient will be the answer. EXAMPLE!. 1. What is the interest of 39Z. lls....
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Every Man His Own Teacher: Or, Lancaster's Theory of Education, Practically ...

John Preston - 1817 - 538 Seiten
...interest is calculated by the Rule of Three, yet there is a short and easy way without a formal statement RULE, Multiply the principal by the rate per cent and divide that product by 100, the quotient will be the interest for one year. Then, multiply the interest of one year by the time,...
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Connolly's Arithmetic: Or, The Ohio Accomptant: Being a Plain Practical ...

James L. Connolly (mathematician.) - 1829 - 266 Seiten
...cent. agreed on. Amount is the principal and interest added together. To find the interest of any sum for a year. RULE. Multiply the principal by the rate per cent. and divide the product by 100, and the quotient will be the answer. Or say, As gl00 : 86 :rg 200 to glSforayear....
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The Tutor's Assistant: Being a Compendium of Practical Arithmetic, for the ...

Francis Walkingame - 1833 - 204 Seiten
...The Amount is the Principal and Interest added together. I. To find the Interest of any Sum of Money for a Year. RULE. Multiply the Principal by the Rate per cent, and that Product divided by 100, will give the Interest required. NOTE. When the Rate is an aliquot part...
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Every Man His Own Teacher: Being an Introduction to Arithmetic, Whereby ...

John Preston - 1834 - 312 Seiten
...321.75 ( [uota. decimal s. Names A days. |$ cts 214.514 82 .625 B 71.5 1 60 .875 )ta. C 143. 3 21 .750 RULE. — Multiply the principal by the rate per cent, and divide that product by 100, the quotient will be the interest for one year. Then, multiply the interest of one year by the time,...
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The Western Arithmetic: Or, Pennsylvania and Ohio Accomptant: Being a Plain ...

James L. Connolly (mathematician.) - 1835 - 264 Seiten
...cent. agreed on. Amount is the principal and interest added together. To find the interest of any sum for a year. RULE. Multiply the principal by the rate per cent. and divide the product by 100, and the quotient will be the answer. Or say, As gl00 : 86 :: g 200 to SI 2 for...
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A Practical and Theoretical System of Arithmetic...: Also, a Treatise on ...

George Willson - 1836 - 202 Seiten
...subjects the creditor to forfeiture of the whole debt. For computing the interest on any sum for 1 year. RULE. Multiply the principal by the rate per cent., and divide the product by 100. 1. What is the interest of .£139 11s. 8^d. for 1 year, at 6 per cent. ? 139 11...
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A Practical and Theoretical System of Arithmetic: Containing a New System of ...

George Willson - 1838 - 194 Seiten
...subjects the creditor to forfeiture of the whole debt. For computing the interest on any sum for 1 year. RULE. Multiply the principal by the rate per cent., and divide the product by 100. 1. What is the interest of £139 11s. 8Jd. for 1 year, at 6 per cent. ? 139 11...
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