The accomptant's oracle; or, key to science, a treatise of common arithmetic


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Seite ii - Four points set in the middle of four numbers, denote them to be proportional to one another, by the rule of three ; as 2 : 4 : : 8 : 16 ; that is, as 2 to 4, so is 8 to 16.
Seite 110 - If 7 men can reap 84 acres of wheat in 12 days, how many men can reap 100 acres in 5 days ? 40. If 7 men can build 36 rods of wall in 3 days, how many rods can 20 men build in 14 days ? , 41.
Seite 191 - To reduce a fraction of one denomination to the fraction of another, but greater, retaining the same value. RULE.
Seite 238 - Multiply as in whole numbers, and give as many decimal places in the product as there are in both the factors.
Seite 135 - CASE 5. To find the principal, when the amount, time, and rate per cent are given.
Seite 130 - To find the interest of any given sum for one year, RULE. Multiply the principal by the rate per cent and divide the product by 100 ; the quotient will be the interest for one year.
Seite 239 - Multiply as in the multiplication of integers, and point off" as many decimal places in the product as there are decimal places in both multiplicand and multiplier.
Seite 111 - If a footman travel 130 miles in 3 days, when the days are 12 hours long ; in how many days, of 10 hours each, may he travel 360 miles ? Ans. 9|f days. 5. If 120 bushels of corn can serve 14 horses 56 days, how many days will 94 bushels serve 6 horses?
Seite 213 - Jhall give the numerator of the quotient. Then multiply the denominator of the dividend by the numerator of the divifor, and their produft Jhall give the denominator.
Seite 179 - Pike and Daboll give both methods. Dilworth's rule for reducing fractions to a common denominator is: "1. Multiply each numerator into all the denominators but its own for a new numerator. 2. Multiply all the denominators for a new denominator." The least common denominator is not mentioned, although it would be very useful in the examples he gives. Pike and Daboll give in addition the method for reducing to a least common denominator. Dilworth does not solve an example or illustrate...

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