| Nathan Daboll - 1813 - 240 Seiten
...third terms to the same denomination, and reduce the second term to the lowest name mentioned in it. 3. **Multiply the second and third terms together, and divide their product by the first term;** and the quotient will be the answer to the question, in the same denomination you left the second term... | |
| Nathan Daboll - 1815 - 240 Seiten
...terms to the same denomination, aiid reduce the second term to the lowest name ir.antioned in it. 3. **Multiply the second and third terms together, and...product by the first term ; the quotient will be the** answer to the question, in the same denomination you left the second term in, which may be brought... | |
| Nathan Daboll - 1818 - 240 Seiten
...terms to the same denomination, and reduce the second term to the lowest naiae mentioned in it. 3. **Multiply the second and third terms together, and...product by the first term, the quotient will be the** answer to the question, in fue same denomination you left the second term in, which may be brought... | |
| John Davidson, Robert Scott (writing master) - 1818 - 172 Seiten
...write the greater as thefirst, and the other as the second proportional. The numbers being thus stated, **multiply the second and third terms together, and divide their product by** thefirst, the quotient will be the answer, in ihe same name in which the third term is9 when you arc... | |
| Beriah Stevens - 1822 - 423 Seiten
...extreme is the divisor. 3. Place the divisor on the left hand, and the other extreme on the right ; **then multiply the second and third terms together, and divide their product by the first,** ami the quotient gives the answer ; which is always of the same name with the middle term. When the... | |
| Nathan Daboll - 1824 - 240 Seiten
...third terms to the same denomination, and reduce the second term to the lowest name mentioned in it. 3. **Multiply the second and third terms together, and...their product by the first term ; the quotient will** b« the answer to the question, in the same denomination you left the second term in, which may be... | |
| Etienne Bézout - 1824 - 219 Seiten
...consequently, for performing the Simple Rule of Three Direct, a« explained in article (179), is as follows ; **Multiply the second and third terms together and divide their product by the first** ; the quotient will be the answer, or fourth term sought. -I he following examples will explain the... | |
| Nathan Daboll - 1825 - 240 Seiten
...second term to the lowest name mentioned in it. 3. Multiply the second and third terms together, and j **divide their product by the first term ; the quotient will be the** answer to the question, in the same denomination you left the second term in, which may be brought... | |
| John White - 1826 - 108 Seiten
...first and third terms into the same denomination, and the second into the lowest name mentioned. 2. **Multiply the second and third terms together, and divide their product by the first,** and their quotient will be the answer, in the same denomination as that in which the second was left.... | |
| Martin Ruter - 1828 - 166 Seiten
...it. Reduce, likewise, the first and second terms to the lowest denomination that either of them has. **Then multiply the second and third terms together,...divide their product by the first term. The quotient** thus obtained will be the answer. It will not be necessary to distinguish between direct and inverse... | |
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