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" Divide the given denomination by that number which it takes of this denomination to make ONE of the next higher. Proceed in this manner with each successive denomination, till you come to the one required. "
An Introduction to the Elements of Algebra: Designed for the Use of Those ... - Seite 73
von Leonhard Euler - 1821 - 216 Seiten
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The American Arithmetic: Adapted to the Currency of the United States ...

Oliver Welch - 1812 - 236 Seiten
...to add in the lowest denomination mentioned; find the sum o£ that denomination ; divide that sum by the number which it takes of this denomination, to make one of the next higher ; set down the remainder, and carry the quotient to the next denomination ; find the sum of the next...
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The American Arithmetic: Adapted to the Currency of the United States; to ...

Oliver Welch - 1857 - 244 Seiten
...lowest denomination mentioned ; find the sum of that denomination ; divide the sum by the numberwhich it takes of this denomination, to make one of the next higher 5 set down the remainder, and carry the quotient to the next denomination ; find the sum of the next...
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An Elementary Treatise on Arithmetic

Silvestre François Lacroix - 1821 - 160 Seiten
...numerator by 20, or dividing the denominator by this number, gives ||*. or 2-/1 s- <"' 2s. 9d. From tbe above example we may deduce the following general...terms, and the last sum will be the fraction required). Tofind the value of a fraction of a higher denomination in terms of a lower, multiply the numerator...
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Conversations on Arithmetic, with Demonstrations to Each Rule

Leonard Pierce - 1823 - 170 Seiten
...by reducing the given number to the lowest denomination mentioned, for a numerator, and placing that number which it takes of this denomination to make one of the next higher, for a denominator. In the example before given, 2 Ib. 6 oz. 16 pwt. 12 gr. if you wi«h to reduce it...
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An Elementary Treatise on Arithmetic: Taken Principally from the Arithmetic of

Silvestre François Lacroix - 1825 - 394 Seiten
...multiplying the numerator by 20, or dividing the denominator by this number, gives a|s. or 2T\s. or 2s. 9d. From the above example we may deduce the following...denominator of this sum by so many as make one of the next denonination, and so on through all the terms, and the last sum will be the fraction required.] To...
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The Juvenile Arithmetick, and Scholar's Guide: Illustrated with Familiar ...

Martin Ruter - 1831 - 190 Seiten
...each other. Add the figures of the first column or denomination together, and divide the amount by the number which it takes of this denomination to make one of the next higher. Set down the remainder, and carry the quotient to the next denomination. Find the sum of the next column...
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Welch's Improved American Arithmetic: Adapted to the Currency of the United ...

1841 - 200 Seiten
...in the lowest denomination mentioned; (6) find the sum of that denomination, divide the • sum by the number which it takes of this denomination to make one of -the next higher, set down the remainder, and carry the quotient to the next denomination ; (6| find the sum of the next,...
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Practical Arithmetic, Uniting the Inductive with the Synthetic Mode of ...

James Bates Thomson - 1846 - 362 Seiten
...required. II. To reduce compound Nos. to higher denominations. Divide the given denomination by that number which it takes of this denomination to make ONE of the next higher. Proceed in this manner with each successive denomination, till you come to the one required. The last...
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Practical Arithmetic, Uniting the Inductive with the Synthetic Mode of ...

James Bates Thomson - 1846 - 402 Seiten
...required. II. To reduce compound Nos. to higher denominations. Divide the given denomination by that number which it takes of this denomination to make ONE of the next higher. Proceed in this manner with each successive denomination, till you come to the one required. The last...
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Practical Arithmetic, Uniting the Inductive with the Synthetic Mode of ...

James Bates Thomson - 1846 - 354 Seiten
...required. II. To reduce compound Nos. to higher denominations. Divide the given denomination by that number which it takes of this denomination to make ONE of the next higher. Proceed in this manner with each successive denomination, till you come to the one required. The last...
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