 | Michael Walsh - 1807 - 290 Seiten
...is the sum per cent.-agreed on. Amount, is the principal and interest added together. GENERAL RULE. Multiply the principal by the rate per cent, and divide the product by 100, and the quotient is the answer for one year.. EXAMPLES. 1 . What is the interest of ¿£.496 for one... | |
 | Elijah H. Hendrick - 1810 - 220 Seiten
...Simple and Compound.!, SIMPLE INTEREST is that which arifes from the principal only. General Rule. I. Multiply the principal by the rate per cent, and divide the product by loo, (or, which is the fame, cut-off two right hand figures in the pounds, which mint be reduced to... | |
 | 1811 - 210 Seiten
...CASE*1!. When the time is one year, and the rate per cent, is pounds or dollars only. * • RULE.» Multiply the principal by the rate per cent, and divide the product by 100. PROOF. , , By the Single Rule of Three. EXAMPLES. 1. What is the interest of 525 L. for 1 year, at... | |
 | Nathan Daboll - 1815 - 250 Seiten
...principal and interest added together. CASE I. To find the interest of any given sum for one year. RULE. Multiply the principal by the rate per cent, and divide the product by 100 ; the quotient will be the answer. EXAMPLE!. 1. What is the interest of 39Z. lls. 8id. for one year at 61. per cent, per annum... | |
 | 1817 - 214 Seiten
...the rate per' cent, is pounds or dollars only. RULE. * Multiply the principality the rate percent, and divide the product by 100 : the quotient will be the interest for 1 year. TROOP. By the Single Rule of Three EXAMPLES. 1. What is the interest of 325L. for 1 year, at 6L. peí... | |
 | Nathan Daboll - 1823 - 262 Seiten
...principal and interest added together. CASE I. To find the interest of any given sum for one yeai» RULE. Multiply the principal by the rate per cent. and divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of S9/. Us. 8itI. for one year, at 61. per cent. per annum... | |
 | Nathan Daboll - 1824 - 264 Seiten
...principal and interest added together • CASE I. To find the interest of any given sum for one year. RULE. Multiply the principal by the rate per cent. and divide the product by 100} the quotient \vill be the answer. EXAMPLES. 1. What is the interest of 391. lls. 8Jd. for one year at 6/. per cent.... | |
 | Nathan Daboll - 1825 - 248 Seiten
...principal and interest addeâ together. CASE i. Vb find {he interest of any given sum for one ysar. RULE. Multiply the principal by the rate per cent. and divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of 391. 11s. SJd. for one year. at 61. per cent, per annum... | |
 | Nicolas Pike, Dudley Leavitt - 1826 - 214 Seiten
...insurance of his property, and is generally at so much per cent. RULE. — Multiply the sum to be insured by the rate per cent. and divide the product by 100 ; — the quotient will be the premium or answer. EXAMPLE. What will be the annual premium for insuring a house against los» *iy... | |
 | Zadock Thompson - 1826 - 176 Seiten
...the interest on any sum in Federal or English money. Rule.f 1. Multiply the principal by the rate, and divide the product- by 100, the quotient will be the interest for one year. 2. Multiply the interest thus found, by the number of years, and the product will be the... | |
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RULE.* Multiply the principal by the 'rate per cent, and divide the product by 100: the quotient will be the interest for 1 year. 
